Does the series Σln(1+e^-n)/n converge?

Click For Summary
SUMMARY

The series Σln(1+e^-n)/n converges, as confirmed by the ratio test. Although the limit approaches 1, which is inconclusive, the series itself is valid for convergence. The confusion arose from mixing terms with e^(-n) and e^(1/n), which are fundamentally different. Properly identifying the series is crucial for accurate analysis and proof of convergence.

PREREQUISITES
  • Understanding of series convergence tests, particularly the ratio test.
  • Familiarity with logarithmic functions and their properties.
  • Knowledge of exponential functions, specifically e^(-n).
  • Basic calculus concepts related to limits and series.
NEXT STEPS
  • Review the ratio test for series convergence in detail.
  • Study the properties of logarithmic and exponential functions.
  • Explore alternative convergence tests, such as the comparison test.
  • Practice solving similar series problems to reinforce understanding.
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators seeking to clarify concepts related to series analysis.

lukatwo
Messages
24
Reaction score
0

Homework Statement



So I need to determine if the series \Sigmaln(1+e^{-n})/n converges.

Homework Equations


The Attempt at a Solution



I know it does, but cannot prove it. Wolfram says that the ratio test indicates that the series converges, but when I try to solve the limit I get that it equals 1(which is not conclusive). here
 
Last edited by a moderator:
Physics news on Phys.org
Do you mean
\sum \frac{ln(1+ e^n}{n}
 
lukatwo said:

Homework Statement



So I need to determine if the series \Sigmaln(1+e^-n)/n converges.


Homework Equations





The Attempt at a Solution



I know it does, but cannot prove it. Wolfram says that the ratio test indicates that the series converges, but when I try to solve the limit I get that it equals 1(which is not conclusive). here

The series you posted looks like ln(1+e^(-n))/n. The series you tested in Mathematics looks like ln(1+e^(1/n))/n. e^(-n) is pretty different from e^(1/n).
 
No it's -n alright, but I've been switching them up along the way. Now I see my problem. Thanks
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
2K