Does the Series $\sum\frac{2}{2^{n}}$ Converge or Diverge?

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SUMMARY

The series \(\sum\frac{n}{2^{n}}\) diverges, as confirmed by the ratio test, which should yield a limit different from 1. The correct application of the ratio test involves evaluating the limit of the ratio of consecutive terms, which should not return a value of 1 if applied correctly. Additionally, the series can be analyzed using a comparison test with the integral of \(x \cdot e^{-x}\), which provides further insight into its convergence behavior.

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  • Understanding of series convergence tests, specifically the ratio test.
  • Familiarity with exponential functions and their properties.
  • Knowledge of comparison tests in series analysis.
  • Basic calculus, including limits and integrals.
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Does the series \sum\frac{2}{2^{n}}


converge??

(Note that bounds on the running index n are from 1 to infinity)

I have tried ratio test but it returned a value of 1 (showing nothing).

I can see from the table function on my calulator that the term eventually diminsh to (not including zero).

Any help would be appreciated.
 
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Can you show how you did the ratio test? The ratio is NOT 1.
 
Rememer, you can pull anything not involving an "n" out of the summation. So the 2 in the numerator can come out. Then you have

2 (SUM) 1/2^n

This can also be written as

2 (SUM) (1/2)^n

You should be able to recognize the SUM as a notable one, and use the rules pertaining to that kind of summation to determine whether or not it converges. And if it converges, does multiplying by 2 change any of that?
 
Sorry fellas the question should read

Does the series \sum\frac{n}{2^{n}}


converge??

(Note that bounds on the running index n are from 1 to infinity)

I have tried ratio test but it returned a value of 1 (showing nothing).

I can see from the table function on my calulator that the term eventually diminsh to (not including) zero.

Any help would be appreciated
 
Ratio test should still not give you a value of 1. Can you show how you got that?
 
What comes to my mind would be doing a comparison test with the integral of x*exp(-x).
 
What Dick said. The ratio test is definitely the test to use. If you got a limit of 1, you're doing something wrong.
 

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