Does the Series Sum of e^n/(1+e^(2n)) Converge?

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SUMMARY

The series sum \( S_n = \sum_{n=1}^{\infty} \frac{e^{n}}{1+e^{2n}} \) converges based on the ratio test. The limit calculated using the ratio test yields \( L = \frac{1}{e} < 1 \), confirming convergence. The discussion also mentions the potential use of the Integral Test, but the ratio test provides a definitive conclusion regarding the series' behavior.

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$\tiny{10.3.35}\\$
$\textsf{Does $S_n$ converge or diverge?}\\$
\begin{array}{lll}
&S_n&=&\displaystyle
\sum_{n=1}^{\infty}\frac{e^{n}}{1+e^{2n}}\\
\end{array}
$\textsf{presume we could use Imtegral test}$
 
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Re: 10.3.35 converge or diverg

Let's try the ratio test:

$$L=\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_{n}}\right|=\lim_{n\to\infty}\left|\frac{\dfrac{e^{n+1}}{e^{2(n+1)}+1}}{\dfrac{e^{n}}{e^{2n}+1}}\right|=e\lim_{n\to\infty}\left(\frac{e^{2n}+1}{e^{2(n+1)}+1}\right)=e\lim_{n\to\infty}\left(\frac{2e^{2n}}{2e^2e^{2n}}\right)=\frac{1}{e}<1$$

Therefore, the series is convergent. :D
 

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