Does the Series $\sum_{n=2}^{\infty} (-1)^n \frac{4}{5\ln{n}}$ Converge?

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SUMMARY

The series $\sum_{n=2}^{\infty} (-1)^n \frac{4}{5\ln{n}}$ converges based on the alternating series test. The key factor is that $\ln(n)$ is a decreasing function, which satisfies the conditions required for convergence. The series can be expressed as $\frac{4}{5} \sum_{n=2}^{\infty} (-1)^n \frac{1}{\ln{n}}$, reinforcing its convergence status. Therefore, this series is confirmed to converge.

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karush
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$\tiny{10.6.10}\\ $
$\textsf{ converge or diverge?}\\$
\begin{align*}\displaystyle
S_n&= \sum_{n=2}^{\infty} (-1)^n \frac{4}{5\ln{n}}\\
&\frac{4}{5} \sum_{n=2}^{\infty} (-1)^n
\frac{1}{\ln{n}}=
\end{align*}
?
??
?

$\textit{converges: alternating series test}$
 
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karush said:
$\tiny{10.6.10}\\ $
$\textsf{ converge or diverge?}\\$
\begin{align*}\displaystyle
S_n&= \sum_{n=2}^{\infty} (-1)^n \frac{4}{5\ln{n}}\\
&\frac{4}{5} \sum_{n=2}^{\infty} (-1)^n
\frac{1}{\ln{n}}=
\end{align*}
?
??
?

$\textit{converges: alternating series test}$

Yes it converges as ln(n) is a decreasing function.
 

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