Klaus_Hoffmann
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i don't know where i saw the question is does this expression (Cesaro sum ??) make sense for big lambda and positive delta
[tex]\sum_{n \le \lambda } (1- \frac{n}{\lambda})^{\delta} \mu (n)=S( \lambda , \delta)[/tex]
for finite lambda the S is finite the question is what would happen as lambda goes to infinity ?, does the sum converge in the sense that for lambda big.
[tex]S \sim A+ O( \lambda ^{-b}[/tex] (b a positive real number)
and the same for
[tex]\sum_{n \le \lambda } (1- \frac{n}{\lambda})^{\delta} \Lambda (n)=S( \lambda , \delta)[/tex]
[tex]\sum_{n \le \lambda } (1- \frac{n}{\lambda})^{\delta} \mu (n)=S( \lambda , \delta)[/tex]
for finite lambda the S is finite the question is what would happen as lambda goes to infinity ?, does the sum converge in the sense that for lambda big.
[tex]S \sim A+ O( \lambda ^{-b}[/tex] (b a positive real number)
and the same for
[tex]\sum_{n \le \lambda } (1- \frac{n}{\lambda})^{\delta} \Lambda (n)=S( \lambda , \delta)[/tex]