Does this line belong to this plane?

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Homework Help Overview

The discussion revolves around determining whether a given line belongs to a plane defined by three points in space. The original poster presents the equation of the line and the coordinates of the points A, B, and C that define the plane.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the line and the plane, questioning the necessity of collinearity between the line and the vectors formed by the points defining the plane. There is mention of calculating the equation of the plane and checking if the line satisfies this equation.

Discussion Status

Participants are exploring different methods to determine the relationship between the line and the plane. Some guidance has been offered regarding finding the equation of the plane using the cross product of vectors derived from the points, and checking if the line meets the plane's equation.

Contextual Notes

There is a suggestion that the original poster may be misunderstanding the conditions under which a line can belong to a plane, as collinearity is not a requirement. The discussion also highlights the need for clarity on how to derive the plane's equation from the given points.

pharoh123
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i am given an equation of a line: [x,y,z]=[-3,-6,-11]+k[22,1,-11]
and i am being asked if it belongs to the plane defined by these three points A(2,5,6) B(-7,1,4) and C(6,-2,-9)
so first i calculated all three vectors between the points so i have AB=[-9,-4,2] AC=[4,-7,-15] BC=[13,-3,-13] and clearly none are collinear with [22,-1,11] so clearly the line is not part of the plane yet the book claims that it is part of the plane. Am i doing something wrong?
 
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pharoh123 said:
i am given an equation of a line: [x,y,z]=[-3,-6,-11]+k[22,1,-11]
and i am being asked if it belongs to the plane defined by these three points A(2,5,6) B(-7,1,4) and C(6,-2,-9)
so first i calculated all three vectors between the points so i have AB=[-9,-4,2] AC=[4,-7,-15] BC=[13,-3,-13] and clearly none are collinear with [22,-1,11] so clearly the line is not part of the plane yet the book claims that it is part of the plane. Am i doing something wrong?
Your given line can be in the plane without having to be collinear with any of the three lines you found. You can determine whether the given line is in the plane by finding the equation of the plane, and then determining whether the given line satisfies that plane equation.

Do you know how to find the equation of a plane given three points in the plane?
 
Mark44 said:
Your given line can be in the plane without having to be collinear with any of the three lines you found. You can determine whether the given line is in the plane by finding the equation of the plane, and then determining whether the given line satisfies that plane equation.

Do you know how to find the equation of a plane given three points in the plane?

yeah i could just put [x,y,z]=A + s*AB + t*AC where t and s are coefficients of the vectors AC and AB
but i don't know how that helps
 
No, I mean find the equation of the plane. The cross product of AB and AC will give you a normal to the plane, say <n1, n2, n3>. Then use any of the points on the plane and the normal to find the equation of the plane.

When you have the equation of the plane, determine whether your line satisfies the plane equation.
 

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