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## Homework Statement

What is the domain and range of the function [itex] y = \frac{2}{x^2-4}[/itex]

## The Attempt at a Solution

I'm lost, and I noticed it seems like a difference of squares so what I did is y = [itex]\frac{2}{(x-2)(x+2)}[/itex]. So the x value of vertex is 0. And i subbed this into the equation to get y = 2/-4

y = -1/2.

I'm guessing Domain is {x[itex]\in[/itex][itex]\Re[/itex]}

and Range is {y[itex]\in[/itex][itex]\Re[/itex] | y [itex]\geq[/itex] [itex]\frac{-1}{2}[/itex]

Is this right?