Domain Differentiation question

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The discussion clarifies that if a function f is differentiable on the interval [0, 2π], its derivative cannot be integrated over the interval [-π, π]. The term "df" refers to the differential of f, while the derivative is denoted as ##\frac{df}{dx}##. The example function provided, f(x), demonstrates that while it is differentiable within [0, 2π], it lacks a derivative outside this range, specifically on [-π, 0], confirming that integration of the derivative is not possible in that domain.

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if a function f is differentiable of [0,2pi] can I integrate its derivative df on [-pi, pi]?
 
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First of all, df is not the derivative of f, it is the differential of f, ##\frac{df}{dx}## is the derivative of x (assuming f is a function of x).

Second of all, why would you think that it's derivative would have a different domain?
 
The function, f(x)= 0 if x< 0 and rational or [itex]x> 2\pi[/itex] and rational, f(x)= 1 if x< 0 and irrational or [itex]x> 2\pi[/itex] and irrational, f(x)= 3 for all other x, is differentiable for all x in [itex][0, 2\pi][/itex] but not differentiable for any other f. Since it does not have a derivative on [itex][-\pi, 0][/itex], no, its derivative cannot be integegrated there!
 

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