Double cheking momentum problem

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SUMMARY

The momentum problem involves a bullet of mass 0.21 kg fired from a gun of mass 5.6 kg, with the gun's recoil speed measured at 2.5 m/s. Using the conservation of momentum equation, the bullet's speed upon leaving the gun is calculated to be 66.6 m/s. The equation applied is m1V2 + m2v2ii = m1v1i + m2v2i, where m1 represents the gun and m2 represents the bullet. The solution confirms that the bullet's speed is indeed 66.6 m/s, validating the calculations presented.

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Homework Statement


A bullet of mass 0.21 kg is fired from a gun of mass 5.6 kg. If the guns recoil speed is 2.5 m/s, what speed must the bullet have as it leaves the gun?


Homework Equations



m1V2 + m2v2ii = m1v1i + m2v2i
m1 = gun, m2 = bullett

The Attempt at a Solution



So,
The terms on the right side drop out.
m1V2 + m2v2ii = m1v1i + m2v2i
m1V2 + m2v2ii = 0
m1V2 = -m2v2ii
divide by m2
m1V2/-m2 = v2ii

(5.6 kg x 2.5 m/s) / (0.21 kg)
-66.6
Since it asks for speed 66.6 m/s
Is this correct I don't have a solution guide thanks.
 
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