Elastic Collision Formula: Solving for Final Velocity and Mass Ratios

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SUMMARY

The discussion focuses on solving for the final velocity and mass ratios in a perfectly elastic collision involving two objects, where mass m1 collides with mass m2 (m2 >> m1). The key equations used are the conservation of kinetic energy and momentum, leading to the final velocity equations V2f = sqrt((m1v1i^2 + m2v2i^2)/(m2)) and V2f = (m1v1i + m2v2i)/(m2). The user identifies a critical relationship where v1i must equal (m2(1 - 2v2i))/(m1) for m1 to stop post-collision, and seeks assistance in verifying this calculation.

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  • Understanding of conservation of momentum and energy principles
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Puddles
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Homework Statement

An object of mass m1 traveling with velocity v1i has a perfectly elastic collision in which it rear ends and object of mass m2 (m2>>m1) traveling with velocity v2i. How must the velocity v1i relate to v2i if the mass m1 is to stop in its tracks (v1f=0)? What happens if velocity v1i is greater than this? If it is smaller?

Relevant equations
KE = .5mv^2
P = mv

The attempt at a solution
Cons Energy
.5m1v1i^2 + .5m2v2i^2 = .5m2v2f^2

V2f = sq.rt(( m1v1i^2 + m2v2i^2 )/(m2))

Cons Momentum
m1v1i + m2v2i = m2v2f

V2f = ( m1v1i + m2v2i )/(m2)

Set equal to each other, but my answer keeps getting more complex? It's a math error, but I'm not sure what it is…

I get to here:(m1^2v1i^2)+(2m1v1im2v2i)+(m2^2v2i^2) = (m1v1i^2)+(m2v2i^2)

Can anyone help me continue to work this out? I'm frustrated because this is a simple problem but I can't get it.
 
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Okay, I think I found my error, I've worked out that v1i = (m2(1 - 2v2i))/(m1), how can I plug this back into check it? I'm struggling to find a way to do so but I know there must be a way…
 
Puddles said:
Okay, I think I found my error, I've worked out that v1i = (m2(1 - 2v2i))/(m1), how can I plug this back into check it? I'm struggling to find a way to do so but I know there must be a way…
Is there a typo there? 1-velocity is dimensionally invalid.
 

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