A symmetrical ladder of mass M = (mass 16.2 kg) leans against a smooth, frictionless wall so the top of the ladder is height h = 6.65 m above the floor, and the bottom of the ladder is distance d = 2.69 m from the base of the wall. Since the floor is also frictionless, a horizontal wire connects the bottom of the ladder to the wall so the ladder does not slip.
a) With no one on the ladder, find T, the magnitude of the tension in the wire.
b) b) Suppose the wire will snap when the magnitude of the tension is T = 230 N. Find x, the distance a man of mass m = 88.1 kg can climb up along the ladder before the wire snaps.
→torque equation obviously
The Attempt at a Solution
a) I would say that the equation is...
0 = -mgh + Fdtan(θ)
F = mgh/(dtan(θ))
tan(θ) = h/d
Am I on the right track?
Also for part (b), I have..
b) The equation I believe is...
0 = -(m + M)gx + Fdtan(θ)
Actually, the answers are not right.