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Drag Force and Power on an inclined plane

  1. Nov 22, 2007 #1
    1. The problem statement, all variables and given/known data

    A 710 kg car drives at a constant speed of 23 m/s. It is subject to a drag force of 500N. What power is required from the car’s engine to drive the car
    a. on a level ground?
    b. up a hill with a slope of 2.0 0?


    2. Relevant equations

    P=Fv


    3. The attempt at a solution

    a) P = (500)(23)?

    b) P = (500cos2)(23)?

    I HAVE NO IDEA.
     
  2. jcsd
  3. Nov 22, 2007 #2

    rl.bhat

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    Homework Helper

    In the second part slope is given. Slope = tan(theta). From that find sin(theta). Now the total drag force during up hill drive = 500 + Mgsin(theta)
     
  4. Nov 22, 2007 #3
    so for b
    its:


    P = (500+ mgsin(theta))(v)
    = [500 + (710)(9.8)(sin2) ](v)
    = 17 085 W?
     
  5. Nov 22, 2007 #4

    rl.bhat

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    Homework Helper

    P = (500+ mgsin(theta))(v)
    = [500 + (710)(9.8)(sin2) ](v)
    = 17 085 W?

    Tan(theta) = 2. Using trigonometrical tables find theta and then find theta or if Tan(theta) = 2. the sin(theta) = (sqrt.5)/2 Use this and find the value.
     
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