Drawing velocity time graphs from distance-time graphs

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SUMMARY

This discussion focuses on the process of drawing velocity-time (VT) graphs from distance-time (DT) graphs, emphasizing the calculation of velocity using the formula v = Δs/Δt. Additionally, it addresses unit conversions, specifically converting 175 kg·m/h² to g·cm/s². The method for unit conversion involves multiplying by conversion factors that maintain the value of one, allowing for the cancellation of units to achieve the desired result.

PREREQUISITES
  • Understanding of distance-time graphs and their interpretation
  • Familiarity with the formula for calculating velocity (v = Δs/Δt)
  • Basic knowledge of unit conversion principles
  • Proficiency in manipulating units and dimensional analysis
NEXT STEPS
  • Study the process of drawing velocity-time graphs from distance-time graphs
  • Learn advanced unit conversion techniques in physics
  • Explore dimensional analysis for complex unit conversions
  • Review examples of velocity calculations in various contexts
USEFUL FOR

Students in physics, educators teaching kinematics, and anyone interested in mastering graph interpretation and unit conversions in scientific contexts.

Alain12345
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Can someone please tell me how to draw a VT graph from this DT graph? Thanks.

Edit: Sorry, one more question. This is about unit conversions though. How do I convert 175 kg x m/h2 to g x cm/s2?
 

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Not being able to see your graph, I can tell you this. Obtain the velocity (velocities?) from your first graph through v=\frac{\Delta s}{\Delta t}. Can you go from here?
 
The trick in units conversions is to keep multiplying by one at each step. Just make your "1" special by putting the target units in the numerator and the existing units in the denominator, and cancel units that show up in both the numerator and denominator of the product. Like if you want to convert 175kg to g,

175kg * (1000g/1kg) = etc.

Or if you want to convert hours^2 to seconds^2,

1hour^2 * (3600seconds/hour)^2 = etc.

Does that make sense?
 

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