Drive line inertia and torsional effects exam question

  • #1
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Hi can anyone help me with this question on inertial forces in gears?
Cheers
Ali :)
 

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  • #2
jack action
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For every shaft [itex]i[/itex], you get:
[tex]\sum T_i = I_i \alpha_i[/tex]
And for every gear [itex]i[/itex] connected to gear [itex]j[/itex], you get:
[tex]\frac{T_{i\ out}}{T_{j\ in}} = \frac{N_i}{N_j}[/tex]
[tex]\frac{\alpha_i}{\alpha_j} = \frac{N_j}{N_i}[/tex]

This gives you 7 equations with 7 unknowns ([itex]T_{A\ out}[/itex], [itex]T_{B\ in}[/itex], [itex]T_{B\ out}[/itex], [itex]T_{C\ in}[/itex], [itex]\alpha_A[/itex], [itex]\alpha_B[/itex], [itex]\alpha_C[/itex]).
 
  • #3
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i would be tempted to apportion an effective moment of inertia to shafts B & C (this takes into account the relative rotation rates)

Select an arbitrary rotation rate for shaft A (say 10 rad/sec)
Calculate the rotational KE of each shaft at this rate
The effective moment of inertia of shafts B and C you calculate by comparing the KE values to that of shaft A
For example :
The KE of shaft A at 10 rad / sec = 75 joules
The KE of shaft B at 5 rad / sec = 0.625 joules, so its effective moment of inertia = 1.5 * ( 0.625 / 75 ) = 0.0125 kg . m^2
Repeat for shaft C then add A, B and C for total effective moment of inertia of the system
 

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