maserati1969
- 24
- 3
Thread moved from the technical forums to the schoolwork forums
Hi all, any thoughts on the following problem please?
When saturated steam is expanded isentropically across a turbine, the dryness fraction should decrease. However, when I calculated the answer to the following question, it actually increased slightly. Any ideas where I went wrong?
Question:
Saturated steam mixture at temperature 330°C with vapour mixture fraction of 0.5 is flowing through a turbine at a flow rate of 6 kg/s. Steam is expanded isentropically to temperature 150°C at the turbine exit. Assume that the turbine external walls are fully insulated (adiabatic turbine). Calculate enthalpy at exit.
My solution:
Using enthalpy formula at inlet (3300C) and data from table: h1 = hf +x.hfg
h1 = 2095.95 kJ/kg
Is isentropic so s1 = s2 So entropy at inlet: s1 = sf +x.sfg
s1 = 4.4969 kJ/kg.K also = s2
Therefore at 150 degrees C: entropy: 4.4969 = 1.8418 + (x.4.9953)
Therefore x = 0.53151 (This should decrease, not increase)
Now use new ‘x’ value for h2:
h2 = 632.18 + (0.53151.2113.8)
h2 = 1755.7 kJ/kg
Many thanks in advance.
Regards
When saturated steam is expanded isentropically across a turbine, the dryness fraction should decrease. However, when I calculated the answer to the following question, it actually increased slightly. Any ideas where I went wrong?
Question:
Saturated steam mixture at temperature 330°C with vapour mixture fraction of 0.5 is flowing through a turbine at a flow rate of 6 kg/s. Steam is expanded isentropically to temperature 150°C at the turbine exit. Assume that the turbine external walls are fully insulated (adiabatic turbine). Calculate enthalpy at exit.
My solution:
Using enthalpy formula at inlet (3300C) and data from table: h1 = hf +x.hfg
h1 = 2095.95 kJ/kg
Is isentropic so s1 = s2 So entropy at inlet: s1 = sf +x.sfg
s1 = 4.4969 kJ/kg.K also = s2
Therefore at 150 degrees C: entropy: 4.4969 = 1.8418 + (x.4.9953)
Therefore x = 0.53151 (This should decrease, not increase)
Now use new ‘x’ value for h2:
h2 = 632.18 + (0.53151.2113.8)
h2 = 1755.7 kJ/kg
Many thanks in advance.
Regards