1. The problem statement, all variables and given/known data The position of a particle moving along the x axis varies in time according to the expression x = 5t^2, where x is in meters and t is in seconds. Evaluate its position at the following times. (a) t = 3.00 s x = ? m (b) t = 3.00 s + Δt xf(final x) = ? m (c) Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 3.00 s. v = ? m/s 2. Relevant equations Maybe lim x->0 ∫Δx/Δt 3. The attempt at a solution (a) x = 45m, got it. (b) I don't understand what it's asking me. (c) lim t-> 0 ∫ 5x^2 Δx/Δt at t=3 = lim t-> 0 [10t] I don't know what to do from here since it asks me to find velocity when t->0 at when t=3 at the same time.