- #1
Dynamics question-answer (classic)
- Thread starter pymn_nzr
- Start date
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- Dynamics
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Homework Help Overview
The discussion revolves around a dynamics problem involving a rolling globe on a gradient, with specific parameters such as initial velocity, radius, and moment of inertia provided. Participants are invited to share their dynamics questions and engage in problem-solving.
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants are discussing the setup of the problem, including the meaning of "slither" in the context of rolling without slipping. There is a request for clarification on what has been attempted so far and where the original poster is experiencing difficulties. Some participants are also sharing their own interpretations of the equations involved.
Discussion Status
The discussion is ongoing, with participants providing guidance on how to approach the problem and encouraging the original poster to clarify their attempts. There is a mix of interpretations regarding the equations presented, and some participants are questioning the correctness of specific terms in the equations.
Contextual Notes
There is a suggestion that the original poster should start new threads for additional questions, indicating a potential constraint on the scope of discussion. Additionally, the clarity of the original poster's language is noted as a point of confusion for some participants.
- #2
tiny-tim
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welcome to pf!
hi pymn_nzr! welcome to pf!
(try using the X2 and X2 buttons just above the Reply box
)
show us what you've tried, and where you're stuck, and then we'll know how to help!
(btw, what does "slither" mean? is the sphere rolling without slipping?
)
hi pymn_nzr! welcome to pf!
(try using the X2 and X2 buttons just above the Reply box
)show us what you've tried, and where you're stuck, and then we'll know how to help!
(btw, what does "slither" mean? is the sphere rolling without slipping?
)- #3
tiny-tim
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hi pymn_nzr!
(please always reply on the thread, not by private message)
your english is a little difficult to understand
if you have more questions that you need help with, just start a new thread (preferably one for each question)
(please always reply on the thread, not by private message
)pymn_nzr said:
your english is a little difficult to understand
if you have more questions that you need help with, just start a new thread (preferably one for each question)
- #4
pymn_nzr
- 9
- 0
is it correct?
[tex]Y=\frac{g\sin \alpha }{2V_{0}^{2}(1-\frac{I}{mR^{2}})}X^{2}[/tex]
[tex]Y=\frac{g\sin \alpha }{2V_{0}^{2}(1-\frac{I}{mR^{2}})}X^{2}[/tex]
- #5
tiny-tim
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pymn_nzr said:
i don't have time to check it properly
, because I'm going out in a few minutes,but i think that minus on the bottom should be a plus