Dynamics: Relative Acceleration

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Master1022
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Homework Statement


The problem is in the image attached below
IMG_6185.JPG


2. Homework Equations


In the working below (although I think I have misunderstood a concept)

The Attempt at a Solution


My attempt is in the attached image.
IMG_6186.jpg


I tried to leave the numbers out until the end. I have not written the exact working as I did it in draft elsewhere. I used the Law of Cosines on the vector triangle, in order to obtain [itex]\vec v_{A/B}[/itex], which came out as 2.057544... m/s. But that is not the correct answer.

Upon reflection, I have realized that I was supposed to draw the vector triangle such that the angle between [itex]- \vec v_{B}[/itex] and [itex]\vec v_{A}[/itex] is obtuse. How should one decide on how to draw the vector triangle?

Many thanks.
 

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You need to construct ##\vec a_A - \vec a_B##, which is the same as ##\vec a_A + (- \vec a_B)##. So, your diagram should show ##\vec a_A## and ## (- \vec a_B)## added together.
 
TSny said:
You need to construct ##\vec a_A - \vec a_B##, which is the same as ##\vec a_A + (- \vec a_B)##. So, your diagram should show ##\vec a_A## and ## (- \vec a_B)## added together.
Thanks for your response, it makes sense now.