E-Fields Question: Finding Zero E-Field & Acceleration

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Homework Help Overview

The problem involves two fixed charges, +Q and +2Q, located along the y-axis of a coordinate plane. The discussion centers on determining if there is a point along the y-axis where the total electric field is zero and calculating the initial acceleration of a small negative charge placed at the origin.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the conditions under which the electric field might be zero between the two charges and discuss the distances from a point on the y-axis to each charge.

Discussion Status

Participants are actively engaging with the problem, questioning the setup and clarifying the relationships between the distances to the charges. Some guidance has been offered regarding the use of symmetry and substitution of values to simplify the calculations.

Contextual Notes

There is some confusion regarding the correct distances to use for the electric field calculations, and participants are encouraged to use specific numerical examples to aid understanding.

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Homework Statement


Two charges, charge one is +Q and charge two +2Q, are fixed in a plane along the y-axis of an x-y coordinate plane. Charge one is at point (0,a) and Charge two is at the point (0,2a).
(a) Is there any portion of the y-axis in which the total electric field is zero? If so, where?
(b) If a small negative charge, -q, of mass m were placed at the origin, determine its initial acceleration (magnitude and direction).

Homework Equations



E1=E2
F=ma
E=F/q
E=1/4pi(epsilon not)xQ/r^2

The Attempt at a Solution



For (a), there will always be an e-field along the y-axis except for a point in between the two charges. I am having trouble finding that point, though. I set the two e-fields equal to each other, but was unsure of what to put as the radius for each.

For (b) I used F=ma and then plugged in F=Eq to get a=Eq/m. My final answer was (-1/4pi(epsilon not)x(Q/a^2+Q/2a^2)xq)/m.
 
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For a) You can use symmetry conditions to find that point. Just think about it logically, where should the E-field go to zero if the 2 charges are equal?

b) Your method is correct. I don't get why you would have an A there since both charges are +Q? Also, the 2a^2 in the denominator of the second term should have parenthesis: (2a)^2
 
For (b) the capital A was supposed to be a Q. And I also mistyped the question--the second charge is +2Q.
 
Ok, then for a)

You have for one charge: E1=kQ/r1^2 and E2=2kQ/r2^2 right. Since you are contained on the y-axis, the distance from a point on the y-axis to your charge 1 and 2 is r1 and r2. That should be relatively easy to find. The variable is y. Find a y such that the two are equal.
 
I think I am still confused on what to substitute for r1 and r2. Should one be y and the other (a-y)?
 
If you are at point y, how far are you from Q1? How far are you from Q2? Those are the values to put for r1 and r2.

If that still confuses you, just put some solid numbers. If I am at y=0, how far am I from Q1 and Q2? What if I were at y=8?
 
So then does y=sqrt(2)a?
 
Thanks a lot for your help! I used real numbers and got the same answer. I understand it much better now.
 

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