Easy Physics P=mv momentum (please answer)

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SUMMARY

The discussion centers on the physics equation for momentum, P = mv, where P represents momentum, m is mass, and v is velocity. The user explores rearranging the equation to M = P/V and examines scenarios with varying values of momentum and velocity. It is established that increasing momentum while keeping velocity constant results in an increase in mass, contradicting the user's initial assumption. The correct interpretation is that an increase in momentum correlates with an increase in mass when velocity remains unchanged.

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This discussion is beneficial for physics students, educators, and anyone interested in understanding the fundamental concepts of momentum and its implications in various physical scenarios.

Gorn
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Hello..

P = MV is the equation for momentum...in order to get the mass a rearrange the equation

such that it looks like this: M = P/V now as an example let's suppose P = 10 and V = 10

So..for example I get M = 10/10
M = 1kg

Questions: What are the 'terms' for momentum and velocity in this equation?

Lets suppose for argument sake that I double the momentum so P = 20 & V =10.

I then come to a conclusion that I do not believe is accurate that if I increase the momentum of an object but not its velocity at the same time I have a decrease in mass ..in this case of 1/2 kilogram? Is that accurate?

Am I correct in assuming that if there is an increase in momentum there is a direct and corresponding increase in velocity?

Is it accurate to conlude that no matter what the increase in momentum there is NO increase in mass?
Thanks for any and all answers
Bye
 
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Gorn said:
Lets suppose for argument sake that I double the momentum so P = 20 & V =10.

I then come to a conclusion that I do not believe is accurate that if I increase the momentum of an object but not its velocity at the same time I have a decrease in mass ..in this case of 1/2 kilogram? Is that accurate?

But you have an increase in mass, m=20/10=2kg. Which is what you would expect.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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