Eccentricity of orbit. Apogee and perigee positions and distances

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    Eccentricity Orbit
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SUMMARY

The discussion focuses on calculating the eccentricity of a satellite's elliptical orbit around the Earth, specifically using the formula e=(A-P)/(A+P), where A is the apogee distance and P is the perigee distance. Participants clarify the relationship between the semi-major axis (a), semi-minor axis (b), and the distance from the center of the ellipse to its foci (c), defined as c=sqrt(a^2 - b^2). The conversation emphasizes the importance of understanding the geometric properties of ellipses in orbital mechanics.

PREREQUISITES
  • Understanding of elliptical orbits and their properties
  • Familiarity with the concepts of apogee and perigee
  • Knowledge of the semi-major and semi-minor axes of an ellipse
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the eccentricity formula for ellipses
  • Explore the geometric properties of ellipses in more detail
  • Learn about orbital mechanics and satellite motion
  • Review relevant equations in textbooks or online resources about ellipses
USEFUL FOR

Students studying physics, particularly those focusing on orbital mechanics, as well as educators seeking to clarify concepts related to elliptical orbits and eccentricity calculations.

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Homework Statement



A satellite is in an elliptical orbit about the Earth. The center of the Earth is a focus of the elliptical orbit. The perigee (C) is the point in the orbit where the satellite is closest to the Earth's center (F). The perigee distance (P) is the distance from the perigee to the Earth's center. The apogee (D) is the point furtheest from the Earth's center. The apogee distance (A) is the distance from the apogee to the Earth's center.

Show that the eccentricity of the orbit in terms of A and P is e=(A-p)/(A+P).

The Attempt at a Solution



Not sure where to begin, i know the distance from the center of the orbit to F is sqrt(a^2 - b^2), where a is the semi-major axis and b is the semi-minor axis.
 
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How is the distance from a focus of an ellipse to the centre calculated?
 


Kurdt said:
How is the distance from a focus of an ellipse to the centre calculated?

I mean the center of the elipse.

Let c equal the distance between the elipse center and a focus.
a = the semi major axis
b = semi minor

c=sqrt(A^2 - b^2)

Is that what you meant?
 


shad0w0f3vil said:
Not sure where to begin, i know the distance from the center of the orbit to F is sqrt(a^2 - b^2), where a is the semi-major axis and b is the semi-minor axis.
The center of the Earth is not at the center of the ellipse. It is at one of the two foci of the ellipse.
 


Sorry my bad, I did already understand that, just struggled to put it into words
 


It's a bit hard to help you here because you left out a very important part of the original post:

Homework Equations



What equations are relevant to solving this problem?
 


If you look up an ellipse in a textbook or even on the internet you'll probably find what you need to do this question.
 


yeh i will just ask my teacher, i can get an answer that isn't wrong, just not sure if its the answer the teacher is looking for.

Thanks for all your help you guys!
 

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