adz7861
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- Homework Statement
- Expression for the total loss of energy after the collision
- Relevant Equations
- p=mv
KE=1/2mv^2
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EENGA 2019 Momentum question -- collision of two masses
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- Collision Momentum Two masses
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Ok, but which option does that match?adz7861 said:
adz7861
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haruspex said:
I keep getting my answer to be C, when the real answer is B
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Then you are making a mistake beyond the working you posted. What you posted matches B.adz7861 said:
adz7861
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The only difference in B & C are the different masses on the nominator. What I've got is the mass of the moving particle (mE) as the nominator. The answer states that it should be ME which is the mass of the stationary particle.haruspex said:
So my working out must be incorrect, unless I'm missing a further step.
I've basically done the KE after the collision - KE before collision to give me a value for the energy loss. I am confused on what to do further after my last equation.
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Can you subtract fractions?adz7861 said:
Write the second term as a fraction with denominato m+M. Show your working.
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Exactly. Get your answer into the form of the choices, a single fraction.adz7861 said: