Effect of Adding NaOH to a Solution of K2CrO4 at Equilibrium

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Discussion Overview

The discussion revolves around the effects of adding sodium hydroxide (NaOH) to a solution of potassium chromate (K2CrO4) at equilibrium, specifically in the context of Le Chatelier's principle. Participants explore the implications of this addition on the equilibrium position of the reaction involving chromate and dichromate ions.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant suggests that adding NaOH would not affect the equilibrium because NaOH is a liquid, expressing uncertainty about this claim.
  • Another participant questions the effect of NaOH on an acidic solution, implying a potential neutralization reaction.
  • There is a suggestion that the reaction will proceed in the forward direction if the acid is neutralized.
  • A participant points out the need for a double-headed arrow in the equilibrium equation to properly represent the reaction condition.
  • Some participants identify H+ as the acid in the reaction and discuss how the addition of NaOH, a base, would affect the equilibrium by removing protons.
  • One participant concludes that the reaction will shift to the left as NaOH takes up protons, although this is not universally agreed upon.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the direction of the equilibrium shift upon the addition of NaOH, with no consensus reached among participants on the final outcome.

Contextual Notes

Participants express uncertainty about the effects of adding NaOH and the implications for the equilibrium position, highlighting a lack of clarity on the definitions and roles of acids and bases in this context.

angel_eyez
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Le chatelier's principle..HELP!

1. for the given reaction at equilibrium predict what would happen if NaOH were added to a solution of K2CrO4



2. 2CrO4 (aq) + 2H+(aq) --> Cr2O7(aq) + H2O



3. my answer was that it would not affect the equilibrium since NaOH is a liquid :confused: but I am nott suure :frown:

all help will be greatly appreciatedd :blushing:
 
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What happens when sodium hydroxide is added to an acidic solution?
 
neutralization reaction?..so that means the reaction will proceed in the forward direction?
 
In your equation, where is the acid? If you neutralize it, what direction will the reaction proceed to reestablish equilibrium.

PS. Your arrow needs to be a double-headed arrow to indicate an equilibrium condition (an absolute requirement for any application of Le Chatelier's principle).
 
so basically da H+ is the acid..cuz acids donate a proton..so therefore the reactino will proceed in the forward direction to reduce the stress of NaOH...? need to know if I am right =)
 
btw ye i know it needs to be a double arrow, i just didnt know how to put it
 
Shift comma, hyphen, hyphen, hyphen, hyphen, shift period.

<---->

You don't have it yet... Think about removing some of the acid. What direction will the reaction proceed to replace it?
 
ohhh..k..so wen NaOH is added it takes up the proton since its a base..so therefore the reaction will proceed to the left =)
 
Final answer?
 
  • #10
um..yeaaa..:|
 

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