Effect of Light Intensity on Photoelectron Kinetic Energy and Emission Rate

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Homework Help Overview

The discussion revolves around the effect of light intensity on the kinetic energy of photoelectrons and their emission rate from a metal surface. The original poster poses a question about how doubling the intensity of light affects the maximum kinetic energy (Kmax) and the rate of photoelectron emission (N), while assuming 100% efficiency.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between light intensity, frequency, and wavelength, questioning how changes in intensity might affect the number of emitted photons and the maximum kinetic energy of photoelectrons.

Discussion Status

Some participants suggest that if the intensity of light doubles, the number of photons would also double, while Kmax would remain unchanged. There is ongoing exploration of these ideas, but no explicit consensus has been reached.

Contextual Notes

Participants note that light intensity is related to the number of photons and energy flux, raising questions about the definitions and relationships between intensity, frequency, and wavelength in the context of the photoelectric effect.

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Homework Statement



A metal gives off photoelectrons with maximum kinetic energy Kmax at the rate of N per second when a beam of light of wavelength λ shines on it. How will Kmax and N change if the intensity (brightness) of light is doubled? Assume 100% efficiency.

Homework Equations



hc/wavelength=? then. P/?=

h=planks constant
c= speed of light
p=power

The Attempt at a Solution



kinetic energy will remain the same
n will double

Im not sure how to do this problem
if the brightness doubles, will the frequency double? or the wavelength?
and I am not sure how that would affect n per second

so what I am basically asking is. Is the intensity of light related to the frequency, and if so, in what way?
 
Last edited:
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stickplot said:

Homework Statement



A metal gives off photoelectrons with maximum kinetic energy Kmax at the rate of N per second when a beam of light of wavelength λ shines on it. How will Kmax and N change if the intensity (brightness) of light is doubled? Assume 100% efficiency.

Homework Equations



hc/wavelength=? then. P/?=

h=planks constant
c= speed of light
p=power

The Attempt at a Solution



kinetic energy will remain the same
n will double

Im not sure how to do this problem
if the brightness doubles, will the frequency double? or the wavelength?
and I am not sure how that would affect n per second

so what I am basically asking is. Is the intensity of light related to the frequency, and if so, in what way?
Light intensity is a measure of the [time-averaged] energy flux and has S.I. units of W.m-2. In other words, light intensity is a measure of the average amount of energy passing through the unit surface. In terms of photons, the intensity of light is directly proportional to the number of photons passing through the unit area per unit time.

Perhaps this will help: http://www.Newton.dep.anl.gov/askasci/phy05/phy05113.htm
 
Last edited:
ok. so does that mean that the photons would double in number since the brightness doubles, and kmax would remain the same.
is this right?
 
stickplot said:
ok. so does that mean that the photons would double in number since the brightness doubles, and kmax would remain the same.
is this right?
Sounds about right to me :approve:
 
alright thanks :)
 

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