Kinetic energy of the photoelectrons

[manaXmizery]

Homework Statement

A beam of ultraviolet light with wavelength of 200 nm is incident on a metal whose work function is 3.0 eV. Note that this metal is applied with +1.0 V with respect to the ground. Determine the largest kinetic energy of the photoelectrons generated in this process.

Homework Equations

Kmax = hf - phi

Kmax = q*|V|

The Attempt at a Solution

I am not entirely sure what the statement about the +1.0 V implies and hence I simply used the formula
Kmax = hf - phi . Substituting the appropriate values gives Kmax = 5.139*10^-19 J . Am I on the correct path ?

 

[DrClaude]

You got the result in the absence of the applied potential. You must now modify the kinetic energy to take into account the potential.

 

[whatphysics]

You got the result in the absence of the applied potential. You must now modify the kinetic energy to take into account the potential.

how do you take into account the potential?

 

[DrClaude]

how do you take into account the potential?

By calculating its effect on the released photoelectron.