Effect of thermal expansion on restraints

Click For Summary
SUMMARY

The discussion focuses on calculating force reactions in restraints when a beam undergoes thermal expansion. Participants emphasize the use of the principle of superposition to analyze the effects of thermal expansion and the resulting forces in fixed restraints, specifically two walls. The formula for displacement, Δx = lαΔT, is highlighted as essential for determining the beam's expansion due to temperature changes. Additionally, stress-strain relationships and Young's modulus are discussed as critical for calculating the forces required to counteract the beam's thermal expansion.

PREREQUISITES
  • Understanding of thermal expansion principles and the coefficient of linear expansion (α).
  • Familiarity with the principle of superposition in structural analysis.
  • Knowledge of stress-strain relationships and Young's modulus.
  • Ability to apply the displacement formula Δx = lαΔT in practical scenarios.
NEXT STEPS
  • Research the application of the principle of superposition in structural engineering.
  • Study the effects of different materials on thermal expansion and stress distribution.
  • Learn about advanced stress-strain analysis techniques for composite materials.
  • Explore the implications of fixed restraints in thermal expansion scenarios in engineering design.
USEFUL FOR

Structural engineers, mechanical engineers, and materials scientists involved in analyzing thermal effects on beams and designing restraint systems.

Ry122
Messages
563
Reaction score
2
When a beam undergoes thermal expansion and the restrains that support the beam are fixed so that no movement is allowed, how do you calculate the force reactions within the restraints? The restraints are two walls, and before expansion occurs no horizontal reaction forces are present.

Since the amount by which the beam is deflected would be equal to the amount by which the beam thermally expands could it be determined with the deflection formula Delta=PL/AE?
 
Engineering news on Phys.org
Hint: think superposition

Assume that there is intially only one wall, and then a force that pushes the beam back "into place".
 
ok but do I use the formula i mentioned above to determine the Force that does that?
 
Yes, assume that the loading happens in two steps. The principle of superposition states that
The net response at a given place and time caused by two or more stimuli is the sum of the responses which would have been caused by each stimulus individually.

In layman's terms, it means that you can take the effect of each load component and add them up to get the sum. Since your bar is fully constrained, the sum effect is no displacement.

So, use your formula to find the displacement that a certain delta T would cause. Then, using stress/strain equations, determine the force and stress required to "push" the beam back into place. That will be your second loading.
 
Delta=PL/AE doesn't have anything to do with delta T though.
Do you mean DeltaTx(Alpha)x(L)=Displacement?
So I don't use Delta=PL/AE at all?

For the stress strain equation would i just use
y=mx
where m = young's modulus
x=percentage strain
and y=stress?

How would the method for doing this change if the first 1/3 of the Beam was made of a material with E=100,000 and the next 2/3 were made of a material with E=200,000?
 
Last edited:
I didn't check your equations, I was simply saying that the thermal expansion causes a change in length.
<br /> \Delta x = l \alpha \Delta T
The constraints will then exert a force back on the beam with the magnitude that negates expansion. I'm not going to do it for you, but your PL/AE equation may come in handy.
 
Would the method for doing this change if the first 1/3 was made of brass of a different cross sectional area to the 2/3 of the beam which is made of steel?
 
The method is going to stay the same, but the implementation would be a little trickier.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 5 ·
Replies
5
Views
7K
  • · Replies 13 ·
Replies
13
Views
21K
Replies
49
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
11K