Effect of time on the acceleration of an object initially at rest?

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Vacuuming effectively involves the application of suction force over time, which influences the acceleration of particles at rest. When a vacuum moves slowly, it allows for a longer duration of force application, increasing the likelihood of overcoming resisting forces like gravity. This extended time enhances the momentum of the particles, enabling them to be lifted more effectively. If the vacuum moves too quickly, the particles may not gain sufficient speed and could fall back down before being fully captured. Therefore, the effectiveness of vacuuming slowly can be attributed to the time factor in overcoming equilibrium between gravitational and suction forces.
howsockgothap
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Hello,

I recently bought a Dyson vacuum and have been excitedly vacuuming my floors way more than I need to! I have been doing some thinking as well on the matter (yes, vacuuming) and have a physics problem/question. It has been a long time since I studied physics, so I am not equipped to answer this myself. Basically: vacuuming is supposedly more effective if done slowly, and it is much easier to pick up slightly larger objects when moving the vacuum at a slower speed. My question is, is this because there is some effect of time on the acceleration or new motion of an object?

I know acceleration is dV/t, but what I mean is, if the same force (suction) is applied to a dust particle at rest, does the time over which that force is applied affect the force's ability to overcome resisting forces? Is applying the same force for a longer period of time (vacuuming over a larger object, say a piece of confetti, more slowly) actually more effective/ would T be a factor in over coming the equilibrium of negative (gravity) and positive (the Dysons suction) forces? And if so... How? Or is there some other explanation for vacuuming slowly working better, probably related to the vacuums brush or some such thing I'd know nothing about?

(And yes, I have considered sweeping up slightly larger objects first, that option is not as fun! )
 
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howsockgothap said:
if the same force (suction) is applied to a dust particle at rest, does the time over which that force is applied affect the force's ability to overcome resisting forces?
It makes a greater change to the momentum, so gives the particle more speed, and lifts it higher. If the force is not applied long enough the particle will simply drop back down when the hose moves on past it.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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