Effective Focal Length of Two Thin Lenses

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The effective focal length of two thin lenses placed 12cm apart with focal lengths of 16cm and 18cm cannot be calculated using the simple formula for lenses in contact. Instead, the back focal length must be considered, which involves determining the image position formed by the first lens before applying the lens formula again for the second lens. A diagram is recommended to visualize the setup and accurately apply the calculations. The correct approach requires careful attention to sign conventions in the formulas used. The initial calculation of 8.47cm is incorrect due to the separation between the lenses.
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Question: Two thin lenses with focal lengths of 16cm and 18cm respectively are placed 12cm apart. what is the effective focal length of this combination of lenses?

I used the formula:

1/f1+ 1/f2 = 1/f effective

My solution:

1/16 + 1/18 = 1/f effective

which gave me an effective focal length of 8.47cm.

Is this right or does the fact that they are put 12cm apart affect the effective focal length?
 
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Your solution assumes that the two lenses are in contact with each other, i.e. there is no distance between the two lenses. What you need is the back focal length, which is the distance from the second lens to the combined focal length of the two lenses.
 
Hootenanny is right.
Draw a diagram. Apply twice the formula 1/f=1/a+1/b. The first time, to find were the first lens forms the image. Draw this position in the diagram. The second time, to find were the second lens forms the image of the {image formed by the first lens}.
Beware of signs!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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