Eigenfunction vs wave function

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Eigenfunctions are specific wavefunctions that yield an eigenvalue when acted upon by an operator, indicating they are eigenfunctions of that operator. A wavefunction can be expressed as a linear combination of eigenfunctions, but not all wavefunctions are eigenfunctions themselves. For example, a superposition of two eigenfunctions does not necessarily result in an eigenfunction of the Hamiltonian. The completeness of a set of eigenstates allows any wavefunction to be represented as a superposition of these eigenfunctions. Precision in terminology is crucial in quantum mechanics to avoid misunderstandings about the properties of quantum systems.
Flavia
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What is the difference between eigenfunction and wave function?

I'm always get confused when i am asked to write wave function and eigenfunction..
 
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An eigenfunction is a type of wavefunction that has an eigenvalue when operated on. It is said to be "an eigenfunction of the operator".
 
Simon Bridge said:
An eigenfunction is a type of wavefunction that has an eigenvalue when operated on. It is said to be "an eigenfunction of the operator".

is this right?

ψ(x,t) = ψ1(x) + ψ2(x)
wavefunction = eigenfunction1 + eigenfunction2
 
Flavia said:
is this right?

ψ(x,t) = ψ1(x) + ψ2(x)
wavefunction = eigenfunction1 + eigenfunction2

Assuming ψ1,ψ2 are eigenfunctions, then yes... Just because the wavefunction is written as the sum of something doesn't mean those somethings are eigenfunctions!

Here's the full description of the situation: You have a quantum system which has only two possible states, 1 and 2. That means there are two quantum states, ψ1 and ψ2 describing the system in either state 1 or 2 (1 and 2 can be spin up or spin down, for example). In general, then, any arbitrary wavefunction can be written as a linear superposition of these two states, \Psi(x,t) = \alpha \Psi_1(x,t) + \beta \Psi_2(x,t). This is possible because the set of eigenstates (ψ1,ψ2) are complete and form a basis.
 
Since the LHS is a function of time as well as position while the LHS is position only, not really. However ... let's say we have a set of wavefunctions \{ \psi_n \} which has been selected so that \mathbf{H}\psi_n = E_n\psi_n ... then each \psi_n is said to be an eigenfunction of the Hamiltonian with eigenvalue E_n.

A system prepared in a superpostion state may have wavefunction \psi = \frac{1}{\sqrt{2}}\left ( \psi_1 + \psi_2\right ) (assuming each \psi_n are already normalized.) In this case \psi is not an eigenfunction of the Hamiltonian.

In general, the set of eigenfunctions of an operator can be used as a basis set. Any wavefunction can. Therefore, be represented in terms of a superposition of eigenfunctions ... including eigenfunctions of another operator. (Just in case someone infers that superpositions of eigenfunctions cannot be eigenfunctions.) It is also possible for a wavefunction to, simultaniously, be an eigenfunction of more than one operator.

Notice how careful I was in the way I phrased things above?
In QM it is very important to be careful about what exactly is being said about a system ... when you are starting out it is as well to get really pedantic about this.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA

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