Eigenfunctions in Hilbert Space, Infinite Square Wells and Uncertainty

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SUMMARY

The discussion centers on quantum mechanics, specifically addressing the properties of eigenfunctions in Hilbert space, the infinite square well, and the uncertainty principle. The ground state of the infinite square well is not an eigenfunction of momentum due to its non-zero width in position space, leading to a zero expectation value for momentum. The uncertainty principle is demonstrated through the relationship between position uncertainty (σx) and energy uncertainty (σH), which is expressed as σxσH ≥ ħ/2m |

|. Additionally, it is established that two noncommuting operators cannot share a complete set of common eigenfunctions, as shown by the commutation relation [P, Q]f = 0.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with Hilbert space concepts
  • Knowledge of eigenfunctions and eigenvalues
  • Basic grasp of the uncertainty principle in quantum physics
NEXT STEPS
  • Study the properties of eigenfunctions in quantum mechanics
  • Explore the implications of the uncertainty principle in various quantum systems
  • Learn about commutation relations and their significance in quantum mechanics
  • Investigate the mathematical framework of Hilbert spaces in quantum theory
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics, as well as educators seeking to deepen their understanding of eigenfunctions and the uncertainty principle.

neo2478
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Hi I'm kinda stuck with a couple quantum HW questions and I was wondering if you guys could help.

First, Is the ground state of the infinite square well an eigenfunction of momentum?? If so, why. If not, why not??

Second, Prove the uncertainty principle, relating the uncertainty in position (A=x) to the uncertainty in energy ([tex]B=p^2/(2m + V)[\tex]):<br /> <br /> [tex]\sigma x\sigma H \geq \hbar/2m |<P>|[\tex]<br /> <br /> For stationary states this doesn't tell you much -- why not??<br /> <br /> And finally, Show that two noncommuting operators cannot have a complete set of common eigenfunctions. Hint: Show that if P(operator) and Q(operator) have a complete set of common eigenfunctions, the [P(operator),Q(operator)]f = 0 for any function in Hilbert space.<br /> <br /> thanks in advance, Rob.[/tex][/tex]
 
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Also can someone tell me why the code thingy for the formulas ain't working??
 
neo2478 said:
Also can someone tell me why the code thingy for the formulas ain't working??

Because the end tag of the tex part is [ / tex ] and not [ \ tex ]
 

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