Eigenstates and repeated measurements

In summary, a measurement of an observable X will cause the wave function to randomly collapse into an eigenstate of X. If a different measurement Y is then made, the wave function will randomly collapse into an eigenstate of Y. This behavior only occurs if X and Y do not commute with each other. Additionally, the system will only remain in the eigenstate if the observable commutes with the Hamiltonian. In interpretations like Quantum Darwinism, which only uses unitary dynamics without collapse, a quantum system can be frozen in an eigenstate through repeated measurements of commuting observables. However, different interpretations of QM all agree on experimental predictions and only differ in their underlying stories about what is happening beyond observation. This has been demonstrated in experiments through
  • #1
jlcd
274
7
A measurement X collapses the wave function randomly into an eigenstate of X. Then if a different measurement Y is made the wave function will randomly collapse into an eigenstate of Y. So for example if you measure position, the wave function will collapse into a narrow peak. Now if you measure momentum, the wave function will collapse into a spread out wave.

Are all eigenstates like that? Or are there examples of eigenstates where if you make repeated measurements, it stays the same?
 
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  • #2
Only if you make repeated measurements of observables that commute with one another. Position and momentum do not commute, which is why the example you describe above behaves the way it does.

An added complication is that although measuring an observable leaves the system in an eigenstate of that operator, the system will only stay in that state if the operator commutes with the Hamiltonian.
 
  • #3
Nugatory said:
Only if you make repeated measurements of observables that commute with one another. Position and momentum do not commute, which is why the example you describe above behaves the way it does.

An added complication is that although measuring an observable leaves the system in an eigenstate of that operator, the system will only stay in that state if the operator commutes with the Hamiltonian.

If you make repeated measurements of observables that commute with one another and the operator commutes with the Hamiltonian. Would it remain the same state if there was no collapse? I was thinking how to analyze it using only unitary dynamics formalism (without collapse).
 
  • #4
To rephrase it. In interpretations like Quantum Darwinism that has unitary only dynamics (without outright collapse). If you make repeated measurements of observables that commute with one another and the operator commutes with the Hamiltonian. Would it remain the same state or not? I guess not and this is why Zurek has to use the ideas of fragments, right? In his theory, states are the primitives and not observations.

Anyone got a clue?
 
  • #5
I guess the answer is the same. That is, in both collapse and unitary only interpretations, one can keep a quantum system frozen in an eigenstate of an observable by repeatedly making the observation, often enough so that significant quantum state evolution has no time to happen before the state is "reset" back (almost certainly) to the nearest eigenstate?

And the difference between collapse and unitary only interpretations is in large object or systems such that without collapse, there will be no objective or classical world? This is why Zurek has to proposed fragments from the einselected pointed states that spread into the enviroment? Without this. We can see both cat but you would see it as male while I can see it as female or different colors? (at least theoretically in a universe without collapse and no einselected pointer states?)

Can someone help. Thank you.
 
  • #6
jlcd said:
I guess the answer is the same.

Different interpretations of QM all agree on all experimental predictions. So all interpretations will agree on what happens in any given experiment. The only thing they disagree on is what story to tell about what happens--what is going on "behind the scenes" where we can't observe.

jlcd said:
one can keep a quantum system frozen in an eigenstate of an observable by repeatedly making the observation, often enough so that significant quantum state evolution has no time to happen before the state is "reset" back (almost certainly) to the nearest eigenstate?

Yes, this has been verified in experiments. It's called the "quantum Zeno effect":

https://en.wikipedia.org/wiki/Quantum_Zeno_effect
 

1. What is an eigenstate?

An eigenstate is a state of a quantum system in which a measurement of a specific observable will always yield the same value. This value is known as the eigenvalue of the observable.

2. How are eigenstates related to repeated measurements?

Eigenstates are related to repeated measurements because when a quantum system is in an eigenstate, repeated measurements of the same observable will always yield the same result. This is due to the fact that the observable's eigenvalue is the only possible outcome.

3. Can a quantum system be in multiple eigenstates at the same time?

Yes, a quantum system can be in a superposition of multiple eigenstates at the same time. This means that the system has a probability of being in each of the eigenstates, and the outcome of a measurement will be one of the eigenvalues with a corresponding probability.

4. What happens to an eigenstate after a measurement is made?

After a measurement is made on an eigenstate, the state of the system will collapse to the measured eigenvalue. This means that the system will no longer be in a superposition of eigenstates, but instead will be in a single eigenstate with a definite value.

5. Are eigenstates always stationary states?

No, not all eigenstates are stationary states. Stationary states are eigenstates of the Hamiltonian operator, while other observables may have different eigenstates that are not stationary. However, stationary states are important because they represent the most stable and long-lasting states of a quantum system.

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