Eigenvalue plots Tannoudji's Quantum Mechanics Vol. II

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SUMMARY

The discussion centers on the eigenvalue plots presented in Tannoudji's "Quantum Mechanics Vol. II," specifically Figure 1 from Chapter XI A./1 on page 1097. The eigenvalues E(λ) are expected to represent straight lines with positive or negative slopes according to first-order perturbation theory, expressed as E(λ) = E_n^0 + λε_1^j. However, the user questions whether the curves depicted are merely illustrative of realistic measurements, as higher-order corrections would introduce non-linear terms, indicating that the actual E(λ) would not be a straight line but a more complex curve.

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  • Understanding of first-order perturbation theory in quantum mechanics
  • Familiarity with eigenvalue equations and their graphical representations
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exciton
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Hi guys,

probably that's the wrong forum, but I was just curious about
the plot (Figure 1 Chapter XI A./1. page 1097 / Volume II) of the eigenvalues

E(\lambda).

If I calculate them they are supposed to be straight lines with positive or
negative slope i.e.:

E(\lambda) = E_n^0 + \lambda \epsilon_1^j

in first order perturbation theory.

Am I missing s.th. or are these curves just ment to be realistic measurement curves
(and if so why isn't there any hint in the text) ?
 
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If you calculate higher order corrections to the energy you will also have term of order \lambda^2 and higher. So the exact value of E(lambda) is not given by a straight line, but some curve instead. The plot gives an example of what the exact value of E(lambda) might be.
 
Thank you very much, it's all about detail :smile:
 

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