i = the 3x3 matrix below
2-λ 0 1
-1 4-λ -1
-1 2 0-λ
Using remainder and factor theorem find the 3 values of λ.
|i| = a1|b2c3-c2b3|-a2|a2c3-c2a3|+a3|a2b3-b2a3|
The Attempt at a Solution
(2-λ) |(4-λ x 0-λ)-(-1x2)|+1|(-1x2)-(4-λ x -1) **because b1 is 0 I've left it out**
(2-λ)[(4-λ)(0-λ)+2] +1 [-2+(4-λ)]
Factorise out (4-λ):
Multiply  brackets out (FOIL):
....and now I'm stuck which probably means I've gona wrong somewhere ;-(
*should I have taken out 0-λ?
*on the 2nd line of my attempted answer I figured the +2 in the first square brackets cancelled out the -2 in the second square brackets, was I wrong?
Thanks for any hints and help :)