Eigenvalues and eigenvectors, 3x3 matrix using Remainder and Factor Theorem

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Homework Help Overview

The discussion revolves around finding the eigenvalues of a 3x3 matrix using the Remainder and Factor Theorem. Participants are examining the characteristic polynomial derived from the matrix and exploring the implications of their calculations.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the determinant formula to derive the characteristic polynomial but expresses uncertainty about their calculations. They question whether they should have factored out a term and whether their simplifications were correct.
  • Some participants suggest factoring the resulting polynomial and finding its roots, while others express confusion about the correctness of the eigenvalues they derived.

Discussion Status

The discussion is ongoing, with participants providing hints about factoring and solving quadratic equations. There is a recognition of potential errors in the eigenvalue calculations, and participants are exploring different interpretations of the polynomial's roots.

Contextual Notes

There is a mention of homework constraints, as participants are navigating the problem without providing complete solutions. The original poster's calculations and assumptions are under scrutiny, which may affect the direction of the discussion.

Jowin86
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Homework Statement



i = the 3x3 matrix below

2-λ 0 1
-1 4-λ -1
-1 2 0-λ

Using remainder and factor theorem find the 3 values of λ.

Homework Equations



|i| = a1|b2c3-c2b3|-a2|a2c3-c2a3|+a3|a2b3-b2a3|

|a|=ad-bc

The Attempt at a Solution

(2-λ) |(4-λ x 0-λ)-(-1x2)|+1|(-1x2)-(4-λ x -1) **because b1 is 0 I've left it out**

(2-λ)[(4-λ)(0-λ)+2] +1 [-2+(4-λ)]

(2-λ)(4-λ)(0-λ)+1(4-λ)

Factorise out (4-λ):

(4-λ)[(2-λ)(0-λ)+1]

Multiply [] brackets out (FOIL):

(4-λ)(λ2-2λ+1)

...and now I'm stuck which probably means I've gona wrong somewhere ;-(

*should I have taken out 0-λ?

*on the 2nd line of my attempted answer I figured the +2 in the first square brackets canceled out the -2 in the second square brackets, was I wrong?Thanks for any hints and help :)
 
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2-2λ+1) can be factored.

If you can't do that, then find the roots: λ2-2λ+1 = 0
 
(4-λ) λ(-2λ)

λ=4 λ=2 λ=0

Is that wrong?

I'm not sure how to find the roots of λ2-2λ+1=0 ?
 
Jowin86 said:
(4-λ) λ(-2λ)

λ=4 λ=2 λ=0

Is that wrong?
Yes, it's wrong
I'm not sure how to find the roots of λ2-2λ+1=0 ?

It's a quadratic equation. Solve it.
 

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