Eigenvalues of Matrix Function

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SUMMARY

The discussion focuses on the proof that a matrix function defined by its Taylor series, f(T) = f0 + f1T + f2T² + ..., inherits the eigenvalues of the original matrix T. Specifically, if T has eigenvalues t1, t2, ..., tn, then the eigenvalues of f(T) are f(t1), f(t2), ..., f(tn). The proof is established by considering an eigenvector v of T and demonstrating that f(T)v = f(ti)v for each eigenvalue ti.

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  • Understanding of matrix functions and Taylor series
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Homework Statement


Define a matrix function f(T) of an nxn matrix T by its Taylor series f(T)=f0 +f1T +f2T2+...
Show that if matrix T has the eigenvalues t1,t2...tn, then f(T) has eigenvalues f(t1), f(t2)...f(tn)


Homework Equations





The Attempt at a Solution


I am at a loss of how to prove this, could someone help me with this problem? I have no idea where to start.
 
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Well, how about a direct calculation? Suppose v is an eigenvector of matrix T with eigenvalue t_1. That is, Tv= t_1v. Okay, so what is T^2v? T^3v, etc?
 
So you'd have T2v=t2v ... Tnv=tnv
 
Then f(T)v=(f0+f1T +f2T2...)v = (f0+f1t1 +f2t2...)v =f(t1)v
 
Then for all eigenvalues... λ=tn f(T)v=f(tn)v , therefore f(B) has eigenvalues f(t1), f(t2),... f(tn)
 

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