Eight-bit 2's complement addition: 01110101 + 11011110

[shamieh]

Perform the following operations involving eight-bit 2's complement numbers and indicate whether arithmetic overflow occurs.

1) 01110101 + 11011110.

So I have a +Positive + a -Negative number. So I just added normally, and got the result of 01010011.

I realized before I started the problem I essentially had 117 +(-34) which is really 117 - 34 = 83.

So my result 01010011 = 83. Was there an easier way I could have done this? And, is this correct? It seems logically correct, but I've been known to screw these up. Also, there would be no overflow right?

 

[Evgeny.Makarov]

Your calculation is correct. The operation results in a carry, but no overflow.