Einstein-Hilbert Action Derive from Christoffel Symbols and Quadratic Lagrangians?

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The discussion focuses on deriving the Einstein-Hilbert action from Christoffel symbols and quadratic Lagrangians as presented in Landau's "Classical Field Theory." The action is expressed as \(\mathcal L = \int dx^{4} \sqrt{-g} g^{ik}(\Gamma^{m}_{il}\Gamma^{l}_{km}-\Gamma^{l}_{ik}\Gamma^{m}_{lm})\). The derivation involves integrating by parts and applying the divergence theorem. Additionally, the constraint \(\mathcal{g}+1 = 0\) is questioned for its physical significance, while the quadratic nature of the Lagrangian in derivatives and fields is noted to be evaluable through functional integrals.

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  • Understanding of Einstein-Hilbert action
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  • Knowledge of quadratic Lagrangians
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  • Study the derivation of the Einstein-Hilbert action in detail
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The discussion is beneficial for theoretical physicists, particularly those specializing in general relativity and field theory, as well as graduate students seeking to deepen their understanding of Lagrangian mechanics and its applications in modern physics.

Kevin_spencer2
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In Landau's bok "Classical Field Theory" pages: 372-373-374 they manage to get the Einstein-Hilbert action (after integrating by parts and use divergence theorem)

[tex]\mathcal L = \int dx^{4} \sqrt (-g) g^{ik}(\Gamma^{m}_{il}\Gamma^{l}_{km}-\Gamma^{l}_{ik}\Gamma^{m}_{lm})[/tex]

from this and definition of 'Chrisstoffel symbols' the Lagrangian would be quadratic in the metric and its first derivatives , if we impose the constraint:

[tex]\mathcal{g}+1 =0[/tex] (does it has any physical meaning??)

and a Qadratic Lagrangian in the derivatives and fields can be evaluated by means of a Functional integral.
 
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Please clean up and edit. The last formula makes no sense.
 

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