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## Homework Statement

A 1 Kilogram object with speed of 2.0 m/s in the positive x direction has a head -on elastic collision with a stationary 0.70Kg object located at x=0. What acceleration does the stationary object experiences during the collision if the collision occurs over 0.2 seconds?

## Homework Equations

m1v1i + m2v2i = m1v1f + m2v2f

## The Attempt at a Solution

m1v1i + m2v2i = m1v1f + m2v2f

(1)(2)+(0.7)(0)=(1)(v1f)+(0.7)(v2f)

v1 +0.7 v2f = 2

plug in:

v1+0.7(2+v1)=2

V1+ 1m +0.7 v1=2

1.7=2-1.4

1.7 v1=0.6

v1=0.6/1.7 =0.353 m/s

v2=2+0.353= 2.353 m/s

m2(v2i-v2f)

=0.7(2.353 -0)

=1.6471=ft

F=1.6471/t=1.6471/0.2=8.24N

a=F/m = 8.24/1= 8.24 m/s^2 final answer

Is this correct? Where did I go wrong? Do I have the everything in the right place?

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