Elastic Collision Problem: Solving for Velocities with Conservation of Momentum

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Homework Help Overview

The problem involves two elastic balls colliding head-on, with one ball having a mass of 50 g and the other being three times that mass. Both balls are initially traveling in opposite directions at the same speed of 15 m/s. The task is to find the velocities of the balls after the collision using conservation principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using conservation of momentum and kinetic energy to derive equations for the final velocities. There is uncertainty about how to handle the two unknowns in the equations. Some participants suggest that having two equations from the conservation laws could help solve for the unknowns.

Discussion Status

Participants are actively exploring the relationships between the variables involved in the collision. Some have provided equations based on conservation principles, while others express confusion about the notation used in external resources. There is acknowledgment of the need to account for the mass ratio of the two balls.

Contextual Notes

Participants note that they are working with two unknowns and are trying to apply the conservation of momentum and kinetic energy equations. There is mention of confusion regarding algebraic manipulation and the interpretation of variables in external references.

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Homework Statement



Two elastic balls, one with mass m = 50 g and the other with mass M = 3m experience a head-on elastic collision after initially traveling in opposite directions at the same speed v = 15 m/s.

Use the conservation of momentum strategy to obtain symbolic expressions and numerical values
for the velocities of the two balls after the collision. (One of the answers is 3E1.)

Homework Equations



Mi1Vi1+Mi2Vi2=Mf1Vf1+Mf2Vf2

The Attempt at a Solution



Well I know that the initial Velocities are going to be the same so

M1+M2(Vi)=M1Vf1+M2Vf2

Would be correct

I'm not sure how you would solve this problem because you are looking for 2 unknowns?

Thanks for any help
 
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The Kinetic Energy is conserved

So I guess KEi=KEf

or

KEi=1/2M1Vi1^2+1/2M2Vi2^2
KEf=1/2M1Vf1^2+1/2M2Vf2^2

Where would I go from there?
 
Last edited:
Weren't you complaining about having 2 unknowns?

So don't you have 2 equations?
 
Ok, I used this equation:

Vi1+Vi2=Vf1+Vf2
Vi1-Vi2=Vf1-Vf2

which would mean

15m/s + -15m/s=Vf1+Vf2
0=Vf1+Vf2
or
Vf1=-Vf2

and

15m/s- -15m/s=Vf1-Vf2
15+15
30m/s=Vf1-Vf2

30m/s=Vf1-Vf1

what am I doing wrong?
 
One mass is 3 times the other.
 
Oh yeah, good point
 
  • #10
I'm trying to take that into account but I'm still lost I think it's because I'm really rusty on Algebra
 
  • #11
Jordash said:
I'm trying to take that into account but I'm still lost I think it's because I'm really rusty on Algebra

Also try using the equations at the link I supplied.

Kinetic energy ... you know that ½mv² thing is also conserved.
Momentum is conserved.

Write them out carefully and solve..
 

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