Elastic Collisions: Conserving Momentum, But Not K.E.?

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SUMMARY

This discussion centers on the principles of elastic collisions, specifically addressing momentum conservation and kinetic energy (K.E.) in a system of five equal masses. When the first ball is displaced, it transfers momentum and energy sequentially to the subsequent balls, conserving both momentum and K.E. However, when balls 2 through 5 are glued together, displacing ball 1 with velocity 'u' results in a scenario where momentum is conserved, but kinetic energy is not, highlighting the complexities of collision dynamics.

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  • Understanding of elastic collisions in physics
  • Knowledge of momentum conservation principles
  • Familiarity with kinetic energy calculations
  • Basic grasp of mass and velocity relationships in collision scenarios
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binbagsss
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assuming collisions are elastic...

right 5 equal masses, if you displace the first ball then you observe balls 2-4 stationary and 5 moves off with equal speed to the right, as all the momentum and energy is passed to ball 2, ball 1 stops, ball 2 then passes all its momentum and energy to ball 3 and then stops etc...

This conserves momentum and k.e.

However, if balls 2 and 5 are glued together, and you displace ball 1 with velocity 'u', then the other 4 must move of withspped 4/u to conseve momentum as mu = 4m*u/4, but then kinetic energy is not conserved...?

thankssss !
 
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binbagsss said:
However, if balls 2 and 5 are glued together,
I assume you mean that balls 2 through 5 are glued together?
and you displace ball 1 with velocity 'u', then the other 4 must move of withspped 4/u to conseve momentum as mu = 4m*u/4, but then kinetic energy is not conserved...?
Don't assume that ball 1 stops dead.
 
Doc Al is right
in case I, ball 1 stops as both ball 1.2 has same mass
but now its different case, ball 1 collides with mass 4m, so it will now recoil!with somewhat lesser velocity than u.
 

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