Elastic collisions in COM frame

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SUMMARY

The discussion focuses on elastic collisions in the center of mass (COM) frame, specifically addressing why the speeds of individual particles remain unchanged post-collision. It is established that the total momentum of the system is conserved, remaining zero in the COM frame both before and after the collision. The equations m1v1 + m2v2 = 0 and m1u1 + m2u2 = 0 illustrate this conservation, confirming that the individual speeds of particles in the COM frame do not change despite variations in the lab frame.

PREREQUISITES
  • Understanding of elastic collisions
  • Familiarity with center of mass frame concepts
  • Knowledge of momentum conservation principles
  • Basic proficiency in algebra for manipulating equations
NEXT STEPS
  • Study the principles of momentum conservation in different reference frames
  • Explore the mathematical derivation of elastic collision equations
  • Learn about energy conservation in elastic collisions
  • Investigate the differences between lab frame and COM frame analyses
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Students studying physics, particularly those preparing for exams on mechanics, as well as educators looking to clarify concepts related to elastic collisions and reference frames.

joriarty
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Homework Statement



Consider an elastic collision of two particles in the centre of mass frame. Briefly explain why the speed of EACH particle after the collision is the same as before the collision.

(FYI this is exam revision so it isn't worth any marks)

The Attempt at a Solution



The centre of mass itself has the same direction, velocity, and momentum after the collision, but I do not understand why the speed of each individual particle (in the COM frame) is the same after the collision. The individual speeds certainly change from the lab frame, and given that the COM frame does not change at all after the collision, the speeds of individual particle speeds should change too, right?

:confused:
 
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The velocity of the CM is zero in the COM frame, so the total momentum of the colliding particles is also zero, both before and after the collision.

Before the collision m1v1+m2v2=0--->v2=-(m2/m1) v1

and after the collision m1u1 +m2u2 =0 --->u2=-(m2/m1) u1.

Write out the equation for conservation of energy, plug in the expressions for v2 and u2. What do you get?

ehild
 
Ah I see what's going on now, thanks!
 

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