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kjean
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Homework Statement
A particle with speed v1 = 2.64 × 10^6 m/s makes a glancing elastic collision with another particle that is at rest. Both particles have the same mass. After the collision, the struck particle moves off at 45º to v1. The speed of the struck particle after the collision is approximately? The answer is 1.9 x 10^6 m/s
Homework Equations
v1i = v1f + v2f
v1i^2 = v1f^2 + v2f^2
v1ix = v1fx + v2fx
0 m/s = v1fy + v2fy
The Attempt at a Solution
I have these equations but I don't understand how to solve it. Can someone please walk me through this problem?
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