- #1
salman213
- 302
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1. A spring is suspended froma ceiling and a 256 g mass is attached to it and pulled down to stretch the spring by 18.2 cm. THe mass is released and travels through the equilibrium position with a speed of 0.746 m/s. Calculate the force constant of the spring/
2. 1/2kx^2 = Ee
1/2mv^2 = Ek
Eg = mgh
3. (DeltaEk - DeltaEg) = DeltaEe
I made my reference point where the spring is stretched until so i guess it has a heigh of 18.2 cm
1/2(0.256)(0.746)^2 - (0.256)(9.81)(0.182) = 1/2k(0.182^2)
and i solve for k
I have another post alread so if u have not read that what then ill tell u here that i have an exam comming up in a few days so i was reviewing my old review problems/tests/ and i found this question on my older test that i screwed up..but he never went through how to do it so i d k how to do it lol
thanks for anyones help in advance:)
This quest
2. 1/2kx^2 = Ee
1/2mv^2 = Ek
Eg = mgh
3. (DeltaEk - DeltaEg) = DeltaEe
I made my reference point where the spring is stretched until so i guess it has a heigh of 18.2 cm
1/2(0.256)(0.746)^2 - (0.256)(9.81)(0.182) = 1/2k(0.182^2)
and i solve for k
I have another post alread so if u have not read that what then ill tell u here that i have an exam comming up in a few days so i was reviewing my old review problems/tests/ and i found this question on my older test that i screwed up..but he never went through how to do it so i d k how to do it lol
thanks for anyones help in advance:)
This quest