(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A spring has a force constant of 30000 N/m. How far must it be stretched for it's potential energy to be 47 J? Answer in units of m.

2. Relevant equations

Us= 1/2k(∆x)^2

3. The attempt at a solution

47= 1/2 (30000)(x)^2

47=15000(x)^2

-14953= x^2

√14953= 122.28

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# Homework Help: Elastic Potential Energy problem

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