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A slingshot will shoot a 10-g pebble 22.0 straight up. How much potential energy is stored in the slingshot's rubber band?

the solution is U = mgy = (10 g)(9.8 m/s^2)(22.0 m) according to the book.

does this mean the potential energy of the slingshot's rubber band is equal to the gravitational potential energy of the pebble? does it also mean the speed of the ball as it comes down is equal to its speed driven by the elastic potential energy of the slingshot's rubber band given air resistance is negligible? i don't get the solution since getting the "U sub el" requires distance from point where the rubber is stretched to the point where it is relaxed times the "k" constant and 1/2. i don't know how to get "k" and "how far it is stretched". yet the solution suggests otherwise. please enlighten me with this problem...

the solution is U = mgy = (10 g)(9.8 m/s^2)(22.0 m) according to the book.

does this mean the potential energy of the slingshot's rubber band is equal to the gravitational potential energy of the pebble? does it also mean the speed of the ball as it comes down is equal to its speed driven by the elastic potential energy of the slingshot's rubber band given air resistance is negligible? i don't get the solution since getting the "U sub el" requires distance from point where the rubber is stretched to the point where it is relaxed times the "k" constant and 1/2. i don't know how to get "k" and "how far it is stretched". yet the solution suggests otherwise. please enlighten me with this problem...

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