1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Elastic properties of solids problem

  1. Dec 14, 2014 #1
    1. The problem statement, all variables and given/known data
    If the shear stress in steel exceeds about 4.0 x 10^8 N/m^2, the steel ruptures. Determine the shear force necessary to punch a 1-cm diameter hole in a steel plate that is 0.5 cm thick.

    2. Relevant equations

    3. The attempt at a solution

    The way I tried to solve this problem was by doing

    4.0 x 10^8 N/m^2 = x/((.005^2)*3.14*.005)

    and solving for x, where x is the amount of newtons necessary to punch the hole in the steel plate. I did this because the ratio of Newtons to m^2 must be 4.0 x 10^8 N/m^2. So I found the area of the plate punched out and solved for x. The solution to this problem is 6.28 x 10^4 N and I got 157 N.

     
  2. jcsd
  3. Dec 14, 2014 #2
    What is the surface area of the hole?
     
  4. Dec 15, 2014 #3
    The surface area of the hole should be 7.85 x 10^-5 m^2.
     
  5. Dec 15, 2014 #4

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    That's not what I get. How are you calculating it?
    You are told the diameter and the depth, and you want the surface area inside the hole.
     
  6. Dec 24, 2014 #5
    Ok I realized my mistake. Thanks!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Elastic properties of solids problem
  1. Elasticity Problem (Replies: 13)

Loading...