Electric Field and Object Mass: Solving for Unknowns

[Octoshark]

Homework Statement

The electric field between the plates of a parallel-plate capacitor is horizontal, uniform and has a magnitude E. A small object with a charge of -2.60 µC is attached to the string. Assume that the tension in the string is 0.350 N, and the angle it makes with the vertical is 10°

What is the magnitude of the electric field?
What is the mass of the object?

Homework Equations

E=Tsin(theta)/q

The Attempt at a Solution

E = (.350)(.1736)/-2.60x10^-6 = 23375 N/C

So I got this, but how does it help me find the mass of the object? Please forgive me if it is simple but I am refreshing on physics as the semester just started last week ;)

 

[Winzer]

Hello octoshark.
I agree with you on the first question.

For the second, what forces are acting vertically?

 

[Octoshark]

-PROBLEM SOLVED-

I didn't realize it was as simple as T=mg/cos(theta) from the way my teacher worded it, it didn't make sense

Answer: 35g

 

[Winzer]

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