Electric field in an off-center hole of an uniformly charged sphere

In summary: This field will be negative because the charge inside the hole is negative. The field from the small sphere will cancel out the field from the large sphere, so the electric field inside the hole will be zero.
  • #1
yiuyan
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0

Homework Statement



Hi, imagine an insulating uniformly charged sphere. Its electric field points from the center outwards radially. Now cut out another smaller sphere from inside, such that their centers do not coincide. What is the electric field inside the hollow like?


Homework Equations


Principle of superposition


The Attempt at a Solution


I figured that by principle of superposition I could subtract the vectors of the old E-field by the E-field due to the removed portion. Is this correct? And it doesn't help in visualizing the pattern too.
 
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  • #2
This is a pretty classic Gauss's Law problem; I've seen it in many textbooks and a friend of mine even saw it on his graduate level EM exam. You are right on the money about the superposition, but doing it your way would be a real headache in terms of finding the field due to this asymmetric weird shape. Instead, superimpose a second sphere of opposite charge density, so that the charge inside is still zero. This will allow you to use Gauss's Law for each sphere.

You should find that one component of the E-field cancels anyway, due to symmetry, and the other component will be some comibation of the charge density [tex]\rho[/tex], the radius of the small sphere, some integers, and the vacuum permittivity[tex]\epsilon_{0}[/tex]
 
  • #3
Thank you for the prompt reply, but I don't really understand it.

How does superimposing a sphere of opposite charge density changes things? Gauss Law is concerned with the charge a surface encloses; if the charges cancel out eventually, there shouldn't be a difference right. Also, if Gauss Law is to be used, where should the surface be drawn at? I didn't use Gauss Law much on this one due to its asymmetry.
 
  • #4
I assume you know how to use Gauss's Law to find the field within a dielectric (nonconducting) sphere. It is a somewhat difficult calculation, but most textbooks show you how to do it. So do this separately for each sphere, the real positive one and the superimposed negative one. Make your surface a spherical shell concentric with the real sphere. Unless you have some information on the relative sizes of the spheres it will be somewhat messier than I hinted above; the version I have seen tells you the radii of the two spheres.
 
  • #5
Sorry I can't really see how Gauss' Law would come in handy in this case. Correct me if I'm wrong, but what Gauss' Law relates is the net flux that comes out of the Gaussian surface is proportional to the magnitude of charge enclosed. It doesn't say anything about the direction or strength of an E-field at any particular point on the surface. Of course unless it is a highly symmetrical one, then we can make necessary assumptions. But in this case, since the smaller sphere is off center, Gauss' Law wouldn't tell us much about the E-field inside the hollow right?
 
  • #6
Gauss's Law absolutely DOES say something about the strength of the E-field, since electric flux is directly proportional to the E-field. That's the reason you use Gauss's Law in the first place - to express the electric field in terms of enclosed charge. For example, you've surely by now used Gauss's Law to find the electric field outside a long charged rod, or an infinite charged sheet, or many other cases...in this situation, you will be finding the electric field within the sphere using GL. As for the direction, usually the field lines are radially inward or outward, like for a point charge.

It doesn't matter that the other sphere is off-center. Use Gauss's Law separately for each sphere and then use the superposition principle for a region inside the smaller one. If you give more specific information; i.e. radii of the spheres and their arrangement, or a picture, we might be able to help more.
 
  • #7
Here is one I've drawn. Sphere with radius R has a smaller hollow sphere inside with radius r (r<R). The distance between their centers is L, and the bigger sphere has uniform charge density rho. How is the E-field inside the hollow like?
 

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  • #8
The field everywhere is just the superposition of two field contributions: (1) the field from the solid sphere of charge of radius R; (2) the field from the sphere of opposite charge of radius r.

Use Gauss's law to find those field contributions. (You can't use Gauss's law directly on the original charge distribution since it lacks symmetry--but you can certainly use it for the spherical distributions.)
 
  • #9
First, use Gauss's Law for the large sphere, and ignore the hole. Derive an expression for the electric field anywhere inside the sphere. Your result should be linear so that as r increases the field increases. Next, use Gauss's Law again for the small negative sphere (BTW I would pick a different letter for its radius, like a or something, so that you don't mix up r from Gauss's Law) and derive an expression for the field inside the negative sphere only. Then simply add your two results together, and evaluate for some spot inside the hole. The only tricky thing will be relating a, R, and L to the r for the spot you've chosen.
 
  • #10
Sorry if I mis phrased my question. I had the idea of getting the E-field in the hole too, what I'm having trouble over is how it looks like. I tried drawing the lines of the big sphere, and the lines of the smaller one and adding them up vectorially, but it was tedious and beyond me. It is possible to do it mathematically, but the result did not help in visualizing the pattern much, only the radial line that joins the two centres. Is there another way?
 
  • #11
I tried to make a VERY rough sketch of what the field lines might look like. Since the field inside get stronger as you approach the surface, I tried to increase the density of field lines near the surface. Inside the hollow, the field is in a uniform direction since the horizontal component of the field cancels. Finally, if you were very far from this thing it should resemble a point charge and all field lines are radially outward and never cross. I hope all these things were conveyed in the picture.
 

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  • #12
Thanks for your answers merryjman, and for taking the time for the sketch. I agree with you that from a very far distance, the E-field would be as if they originated from a point charge. But I can't see how the E-field inside the hollow can be horizontal.
I've made another sketch, a rather similar one. The bigger dark gray sphere has uniform positive charge density rho, and so its E-field is nice and points radially outward. Now the smaller sphere has uniform charge density rho too, but negative now. Such that by putting it in, we effectively create a hollow sphere with no enclosed charge. Now if we do the same addition for the E-fields, by superposition; what I see is that there is only one radial component of the E-field, and that is the one which passes through both centers. The remaining E-field have to be added, and that is the part that causes confusion. Do correct me where I went off track. Thanks.

merryjman said:
I tried to make a VERY rough sketch of what the field lines might look like. Since the field inside get stronger as you approach the surface, I tried to increase the density of field lines near the surface. Inside the hollow, the field is in a uniform direction since the horizontal component of the field cancels. Finally, if you were very far from this thing it should resemble a point charge and all field lines are radially outward and never cross. I hope all these things were conveyed in the picture.
 

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  • #13
http://webapps3.ucalgary.ca/~dppvan/phys259/examples/Sphere%20with%20a%20hole%20in%20it.pdf [Broken]

It illustrates everything in a very accessible way. Credits to University of Calgary for uploading that file.
 
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What is an electric field in an off-center hole of an uniformly charged sphere?

An electric field in an off-center hole of an uniformly charged sphere refers to the strength and direction of the electric force experienced by a charged particle placed at a point within the hole of the sphere. This field is created by the distribution of charge on the surface of the sphere and is affected by the location of the hole relative to the center of the sphere.

What factors affect the electric field in an off-center hole of an uniformly charged sphere?

The electric field in an off-center hole of an uniformly charged sphere is affected by the magnitude and distribution of charge on the surface of the sphere, as well as the distance and orientation of the hole from the center of the sphere. Additionally, the size and charge of the particle placed at the point within the hole can also impact the electric field.

How can the electric field in an off-center hole of an uniformly charged sphere be calculated?

The electric field in an off-center hole of an uniformly charged sphere can be calculated using the Coulomb's Law, which states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Additionally, the concept of electric potential can also be used to calculate the electric field in this scenario.

What is the significance of the electric field in an off-center hole of an uniformly charged sphere?

The electric field in an off-center hole of an uniformly charged sphere has practical applications in various fields such as electrical engineering, physics, and materials science. It helps in understanding the behavior of charged particles in electric fields and can be used to design and optimize various electronic devices and systems.

How does an off-center hole affect the electric field in a uniformly charged sphere?

An off-center hole in a uniformly charged sphere can significantly alter the electric field within the sphere. This is because the charge distribution on the surface of the sphere is no longer symmetric, leading to variations in the electric field strength and direction at different points within the hole. The closer the hole is to the center of the sphere, the more pronounced the effect on the electric field.

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