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Electric Field in the matter - D the displacement field

  1. Jun 10, 2009 #1

    pbp

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    Hi,

    I try to understand the concept of the displacment field and the Gauss Law for it (the total flux equals to Q free )
    1. The problem statement, all variables and given/known data
    for example I try to find the electric field produced by a uniformly polarized sphere of radius.

    3. The attempt at a solution
    I try to solve this problem in two ways:
    the first one is to calculate the bounded charge (equals to Pcos(teta)) and from this to calculate the potential and hence the field.
    My second approach (whic probably mistaken approach) is to do the following: Since we know that the D=epsilon_0 * E +P and also according to Gauss law we know that the flux thorugh a Gaussian surface equals to the Q_free_in I built a gaussian surface inside the sphere, the total charge equals to zero and therefore I conclude that D equals to zero(the field inside the sphere is uniform) . If so, I can conclude that E= -p / (epsilon_0).

    In each way I got 2 different answers....
    where is the problem ?
     
  2. jcsd
  3. Jun 10, 2009 #2

    gabbagabbahey

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    Homework Helper
    Gold Member

    You seem to be saying that for a concentric spherical Gaussian surface [itex]\mathcal{S}[/itex] of radius [itex]r[/itex], you would get:

    [tex]\int_{\mathcal{S}} \vec{D}\cdot\vec{da}=4\pi r^2 |\vec{D}|[/tex]

    ....is that really true?....Don't there have to be a couple of restrictions (symmetries) on [itex]\vec{D}[/itex]? :wink:
     
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