1. The problem statement, all variables and given/known data The electric field at the point x=5.00 cm and y=0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x=10.0 cm and y=0, the electric field points in the positive x direction with a magnitude of 15.0 N/C. Assuming the field is produced by a single point charge, find (a) it's location and (b) the sign and magnitude of its charge 2. Relevant equations E= kq/r^2 3. The attempt at a solution 1.5E1=E2 1.5 kq / x^2 = kq/ (x-5)^2 1.5(x-5)^2 = x^2 used quadratic, got x=27.2 , assumed charge is positive because E field strength increases as you move in the positive x direction. BUT I think my reasoning might be wrong..