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dchrisma
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Homework Statement
The dipole moment of the water molecule is 6.17 x 10^-31 C*m . Consider a water molecule located at the origin whose dipole moment points in the +x-direction. A chlorine ion , of charge -1.60*10^-19, is located at x= 3.00*10^-3 m.
Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used.
Question: Find the magnitude of the electric force that the water molecule exerts on the chlorine ion.
Homework Equations
p=qd
F= k(q1q2)/d^2
The Attempt at a Solution
Not sure what to do at this point. I tried to use the electric dipole moment equation to find the charge of the water molecule since p and d
were given. Knowing that charge, I placed the variables into the force equation but to no avail. There's definitely more to this than I'm seeing. Isn't that force equation only related to point charges? I don't believe either particle is a point charge in this case. Can someone send me in the right direction?